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matrenka [14]
3 years ago
7

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.

Mathematics
2 answers:
o-na [289]3 years ago
4 0

Answer:

71.4

Step-by-step explanation:

cos 6 = 71 / x = 71.4

djyliett [7]3 years ago
3 0

Answer:68.2

Step-by-step explanation:

cos6=71/EF

cos6= 0.960170286650366

0.960170286650366= 71/EF

0.960170286650366*71=EF

EF= 68.2

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