Answer:
They lose about 2.79% in purchasing power.
Step-by-step explanation:
Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.
Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about
... (1 +0.03/365)^365 ≈ 1.03045326
Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...
... 1.03045326 / 1.06 ≈ 0.9721 . . . items
That is, the loss of purchasing power is about ...
... 1 - 0.9721 = 2.79%
_____
If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.
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Answer:
2
Step-by-step explanation:
(,)=?
(,)=(5,2)
=5!(2!(5−2)!)
=5!2!×3!
= 10
Answer:
-3(4+2n) multiply -3 by 4 and 2n
-12-6n
27x^3 - 12x factors into
3(9x^3 - 4x) a common factor of three has been taken out.
3x(9x^2 - 4) a common factor of x has been taken out. 3x is not a linear factor.
9x^2 - 4 factors by means of the difference of squares
3x(3x - 2)(3x + 2)
The two linear factors are 3x - 2 and 3x + 2
