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3 years ago

Part E

Mathematics

1 answer:

iVinArrow [24]3 years ago

6 0

El petróleo cumple una triple función en la sociedad: fuente de energía, materia prima y fuente de ingresos.

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What is 0.96 rounded to the neatest tenth.

Alona [7]

Answer:

1.0

Step-by-step explanation:

6 is greater than 5 therefore it rounds 9 up to the next number which is 10, 1.0 or just 1.

4 0

3 years ago

Read 2 more answers

Please help ASAP. Please include steps to answer the question, thank you!

ziro4ka [17]

Answer:

i have no idea but thx 4 the points

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

R=8 P=7 R+P= PLZ im stuck <br>

mihalych1998 [28]

Answer:

Step-by-step explanation:

The equation is just a plug in and solve. you have your given variables and all you have to do it plug them into the matching spot and solve

R=8 P=7

8+7=15

7 0

3 years ago

Melissa Costouras obtains a $3,000 loan for darkroom equipment. She makes six monthly payments of $511.18. Determine the APR.

nasty-shy [4]

Using the simple interest formula, it is found that the APR for the loan is of 4.472%.

<h3>What is the simple interest formula and when it is used?</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

$A(t) = A(0)(1 + rt)$

In which:

A(0) is the initial amount.

r is the interest rate, as a decimal.

The parameters for this problem are:

A(t) = 6 x 511.18 = 3067.08, A(0) = 3000, t = 0.5.

We solve the equation for r to find the APR.

$A(t) = A(0)(1 + rt)$

$3067.08 = 3000(1 + 0.5r)$

$1 + 0.5r = \frac{3067.08}{3000}$

1 + 0.5r = 1.02236

r = (1.02236 - 1)/0.5

r = 0.04472.

More can be learned about simple interest at brainly.com/question/25296782

#SPJ1

5 0

1 year ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago