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3 years ago

Somebody help me please

Mathematics

1 answer:

Scrat [10]3 years ago

6 0

Answer:

Other dude is correct

Step-by-step explanation:

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The sum of two numbers is 28. one number is 14 more. find the numbers

ruslelena [56]

The numbers are: "7 " and "21 " .
_______________________________________
Explanation:
_______________________________________
The numbers are: "x" and "x + 14" .

x + (x + 14) = 28 . Solve for "x" ; and then solve for "x + 14" .
_______________________________________
→ x + (x + 14) = 28 ;

Rewrite as:

→ x + x + 14 = 28 ;

→ 1x + 1x + 14 = 28 ;

→ 2x + 14 = 28 ;

Subtract "14" from each side of the equation;

→ 2x + 14 − 14 = 28 − 14 ;

 → 2x = 14 ;

Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;

→ 2x / 2 = 14 / 2 ;

→ x = 7 .
_________________________________________
So; one of the numbers is: " 7 " .

The other number is: " x + 14 " ; which equals: " 7 + 14 = 21".

The other number is: "21 " .
_________________________________________
The numbers are: "7 " and "21 " .
_________________________________________

5 0

3 years ago

What should you do when solving consecutive integer problems

Lemur [1.5K]

Step 1. Identify the variable.
Step 2. Write an algebraic equation.
Step 3. Solve the equation.
Step 4. Answer the equation.
Step 5. Check answer.
Hope this helps...?

3 0

3 years ago

PLEASE HELP! THANK YOU! :D

Ostrovityanka [42]

I think it’s C. Sorry if I’m incorrect

6 0

3 years ago

Read 2 more answers

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

Step-by-step explanation:

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

The Quadratic Formula: For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

3 years ago

Read 2 more answers

Ms. Zab gave a group of 5 students a total of 18.75 liters of water for a science experiment. If each student in the group used

wlad13 [49]

Answer: The quantity of the water received by each student = 3.75 liters.

Step-by-step explanation:

Given: Total water = 18.75 liters

Total students =5

If each student in the group used the same amount of water for their experiment, then the quantity of the water received by each student = $\dfrac{\text{Total quantity}}{\text{Total students}}$

$=\dfrac{18.75}{5}\\\\=3.75\ liters$

The quantity of the water received by each student = 3.75 liters.

4 0

3 years ago