Answer:
A. Point D could be the image of B.
D is up and to the right of B, so yes. Select choice A
B. Point C could be the image of A.
C is below A, so no
C. Point E could be the image of C.
E is up and to the right from C so yes, Select choice C
D. Point D could be the image of A.
D is down and to the right of A so no.
E. Point E could be the image of B.
E is up and to the right of B so yes. Select choice E
F. Point C could be the image of E.
No C is down and to the left of E.
Answers: A C E
Step-by-step explanation:
1.7=2
8.1=8
6.9=7
4.3=4
Hope this helps
Answer:
2.3 could, but not -0.25.
Step-by-step explanation:
It is impossible to have any probability larger than 100 or lower than 0. 2.3 is possible bc it's below 100 and above 0.
The ratio of red to green is 5:6 which means that for every 5 red cars, there are 6 green cars
The ratio of green to blue is 3:10 telling us that for every 3 green cars, there are 10 blue cars.
The ratio 3:10 is equivalent to 6:20 after we multiply both parts by 2. This now says that for every 6 green cars, there are 20 blue cars.
------------------------------
Let's say we had 5 red cars, 6 green cars and 20 blue cars
Based on that info, we know that the ratio of red to green is 5:6
And the ratio of green to blue is 6:20 which reduces to 3:10
We don't reduce 6:20 to 3:10 however, since that would change the green count from 6 to 3. We want to keep the green count at 6.
So because there are 5 red cars, 6 green cars, and 20 blue cars in this example, and this example points to the proper ratios mentioned earlier, this means that the final answer is 5:6:20. This ratio cannot be reduced or simplified as there are no common factors (other than 1) for 5, 6, and 20.
