Answer:
The required volume is 5 ml.
Step-by-step explanation:
Given : In tests for intoxication, blood alcohol levels are expressed as percentages by volume. A blood alcohol level of 0.080% by volume means 0.080 mL of ethanol per 100 mL of blood and is considered proof of intoxication. If a person's total blood volume is 5.0 L.
To find : What volume of alcohol in the blood gives a blood alcohol level of 0.100 % by volume?
Solution :
According to question we use the formula,

The percentage of a blood alcohol level is 0.100%
The total volume of the blood is V=5L=5000 ml.
Substitute the value in the formula,




Therefore, the required volume is 5 ml.
Answer:
DGF = 106
Step-by-step explanation:
Bisects means to divide in half, with two equal parts
DGF = DGE + EGF
DGE = EGF
DGF = DGE + DGE
DGF = 53+53
DGF = 106
How far would the cheetah have traveled in the first eight minutes? show how you arrived at your answer
Answer:
B is the correct answer.
Step-by-step explanation:
graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).
We have the equation:

We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.

Now, we use the point (2, 108/25) to calcualte b:
![\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D3%5Ccdot%20b%5Ex%20%5C%5C%20%5Cfrac%7B108%7D%7B25%7D%3D3%5Ccdot%20b%5E2%20%5C%5C%203%5Ccdot%20b%5E2%3D%5Cfrac%7B108%7D%7B25%7D%20%5C%5C%20b%5E2%3D%5Cfrac%7B108%7D%7B25%5Ccdot3%7D%3D%5Cfrac%7B108%7D%7B3%7D%5Ccdot%5Cfrac%7B1%7D%7B25%7D%3D%5Cfrac%7B36%7D%7B25%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B%5Cfrac%7B36%7D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B%5Csqrt%5B%5D%7B36%7D%7D%7B%5Csqrt%5B%5D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B6%7D%7B5%7D%20%5Cend%7Bgathered%7D)
Then, we can write the equation as: