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givi [52]
3 years ago
5

What's the cost of the # of cookies?

Mathematics
2 answers:
77julia77 [94]3 years ago
8 0
You would choose a cost that will increase each time a cookie is added
pochemuha3 years ago
8 0
Try 3 :)))) hope it helps
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The ratio of dark chocolate candies to white chocolate candies is 3 to 2. There are 18 pieces of dark chocolate. How many pieces
ch4aika [34]

there are 18 pieces of dark chocolate and the ratio of dark and white is 3:2 so we can divide 18 by 3.

18/3 = 6.

This means the ratio of dark chocolate to white as a 1:1 ratio would be 6:6 so we can multiply 6 by 2 to give us the total amount of pieces of white chocolate.

6*2 = 12.

Therefore there are 12 white chocolate pieces.

4 0
3 years ago
Fraction that is smaller than -2^1^3
lapo4ka [179]
Isn't it 1/8?
I hope this helped i think i just simplified xD

7 0
3 years ago
A pizza will be split among 3 friends.<br> What amount of pizza will each<br> friend receive?
lozanna [386]

Answer:

1/3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

6 0
3 years ago
The sum of two consecutive intergers is no more than 209 . Whatbis the large of two integers
soldi70 [24.7K]

104 and 105 are consecutive numbers that add up to 209. Maybe this answers your question? Let me know otherwise.

8 0
3 years ago
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