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devlian [24]
3 years ago
9

The perimeter of an equilateral triangle is 63 inches. Suppose a square is constructed with each side being 2 inches shorter tha

n each side of the triangle, and then 3 inches are added to each side of the triangle. How many inches would the total combined perimeters of the triangle and square be?
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Combined perimeters of the triangle and square will be 148 inches

Step-by-step explanation:

An equilateral triangle has all its sides have equal length. The perimeter is 3l where l is length of one side.Given the perimeter of the equilateral triangle as 63 inches then,finding the length of each side will be:

3l=63

l=63/3=21 inches.

Square has its lengths 2 inches shorter than each side of triangle,this will be;

21-2=19 inches

Perimeter of the square will be 4l = 4*19=76 inches

In the new triangle 3 inches are added to each side,thus the new side will be;

21+3=24 inches.

New perimeter of triangle will be: 3l = 3*24=72 inches

The new combined perimeter will be 76+72=148 inches.

Learn More

Perimeter of an equilateral triangle : brainly.com/question/11068968

Keywords :Perimeter,equilateraltriangle, square

#LearnwithBrainly

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36 x in 2

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What is the value of cos(tan-1(0))?<br><br> –1<br> 0<br> 1<br> StartFraction pi Over 2 EndFraction
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4 0
3 years ago
In J, K is the midpoint. The coordinates of ) are (2, 2), and the coordinates of Kare (10, 11). What are the coordinates of L?
DiKsa [7]

Answer:

L(18, 20)

Step-by-step explanation:

In JL, K is the midpoint. The coordinates of J are (2, 2), and the

coordinates of K are (10, 11). What are the coordinates of L?

Solution:

If O(x, y) is the midpoint between two points A(x_1,y_1) and B(x_2,y_2). The equation to determine the location of O is given by:

x=\frac{x_1+x_2}{2} \\\\y=\frac{y_1+y_2}{2}

Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let (x_2,y_2) be the coordinate of L. Therefore:

10=\frac{2+x_2}{2} \\\\20=2+x_2\\\\x_2=18

11=\frac{2+y_2}{2} \\\\22=2+y_2\\\\y_2=20

Therefore L = (18, 20)

4 0
2 years ago
What the equations are
strojnjashka [21]
So, first lets define our variables: 
 
let x = the number of dimes
let y = the number of nickels

so our first equation would be x+y = 16

Since dimes are 10 cents and nickels are 5 cents the next equation would be as follows: 

.10x+.05y = 1.35

now change the first equation so y = -x+16
now substitute:

.10x+.05(-x+16) = 1.35
then multiply so you get .10x+-.05x+0.8=1.35

combine like terms and you get .05x+0.8 = 1.35
then subtract 0.8 from both sides and you get .05x = 0.55 then subtract
and you get x = 11 then substitute 11 for where x should be and you should get y = 5

So, you have 11 dimes and 5 nickels 
6 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Makovka662 [10]
The answer is 26.19. It’s 100% right.
4 0
2 years ago
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