Question

Periodic grab some phase shifts

Answer 1

Answer:

The sine function is:

$y(x)=\frac{2}{3}sin[3\pi (x-\frac{2\pi}{3})]-2$

Step-by-step explanation:

We need to recall that a sine function can write as:

$y(x)=Asin[B(x+C)]+D$

Where:

• A is the amplitude of the function
• B is the period
• C is the phase shift left
• D is the vertical shift

So we just need to use the listed attributes

Therefore, the sine function is:

$y(x)=\frac{2}{3}sin[3\pi (x-\frac{2\pi}{3})]-2$

I hope it helps you!