Answer:
-14√2
Step-by-step explanation:
Note that 18 = 2*9, and that 9 is a perfect square. Therefore,
2*√18 = 2*3*√2, or 6√2.
Next, note that 32 = 2*16, and that 16 is a perfect square. Therefore,
-5*√32 = -5*√2*√16, or -5*√2*4, or -20√2.
Combining these two results, we get:
6*√2 - 20√2, or -14√2
Answer: You add up all the terms given of EACH angle, and make this an addition problem that is "equal to 180" ; since all triangles have three angles that add up to 180 degrees. Then you solve for "x".
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(as follows) ; to get: " x = 29 ⅔ ° " .
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3x + 4 + 2x + x + 8 = 180 ;
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Combine the "like terms" ;
3x + 2x + x = 6x ;
4 + 8 = 12
So, we have: 6x + 12 = 180 ;
Now, subtract "12" from each side of the equation:
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6x + 12 − 12 = 180 <span>− 12 ;
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to get:
6x = 178 ;
Now, divide EACH SIDE of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ;
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6x / 6 = 178 / 6 ;
to get: x = 178/6 = 29 ⅔ ° .
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x = 29 ⅔ ° .
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.92 because if you travel 55 miles every hour, you would divide the distance traveled by 60 minutes and find you travel .92 miles per minute
The number of minutes it will take 5 machines to make 15 widgets is 90 minutes
Given that :
The time taken to make a widget is directly proportional to the number of widgets made and inversely proportional to the number of machines utilized.
Using the variation protocol defined :
Let :
n = number of widgets made
n = number of widgets made m = number of machines used
n = number of widgets made m = number of machines used t = time taken
Hence, from joint variation :
t α n α 1/m
t = kn/m
Where k = constant of proportionality :
Solving for k
When t = 10, n = 5, m = 15
10 = (k × 5) / 15
15 × 10 = 5k
150 = 5k
k = 150 / 5
k = 30
Equation becomes :
t = 30n/m
Solve for t ;
When m = 5 ; n = 15
t = (30 × 15) / 5
5t = 450
t = 450 / 5
t = 90
Hence, it will take 90 minutes.
Learn more : brainly.com/question/18796573
Answer:
1:2
Step-by-step explanation:
Put the numbers as a ratio
4:8 Simplify this ratio by dividing both sides by 4
1:2 This is the ratio of baskets to number of attempts in its lowest terms
