Question

A rectangle’s length is 9 more than 4 times its width. The area of the rectangle is 90 square inches. What is the width of the rectangle?

Answer 1

Answer:

15/4 in or 3.75 in

Step-by-step explanation:

Find your equations:

L = 4w + 9 in

A = L*w = 90 in^2

Substitute L:

L*w = 90 in^2  <--  L = 4w + 9

(4w + 9in)w = 90 in^2  

4w^2 in^2 + 9w in = 90in^2

Solve Simultaneously:

w = -6 in, 15/4 in

Width is positive so it is 15/4 in or 3.75 in.

Double check:

(4w + 9in)w = 90 in^2  

(4*3.75in + 9in)(3.75in) = 90 in^2

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