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Olegator [25]
3 years ago
8

What are the steps to get 1/7

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

1/7 is your answer. It can't be reduced any further. If there is supposed to be a problem, next time, add it.

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you have $200 in a savings account. each week for 8 weeks, you take out $18 for spending money. how much money is in your accoun
Furkat [3]
200 - 8 * 18 = 56
Total money - Week * Cost per week
5 0
3 years ago
Read 2 more answers
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
4 years ago
How do you write <br> 17<br> 25<br> as a percentage?
Sonja [21]

is that supposed to be written as a fraction and you are looking for a percentage?


5 0
3 years ago
Read 2 more answers
The value of a ratio is __________.
Korolek [52]

Answer:

B.

Step-by-step explanation: The value of a ratio is the quotient of the two quantities in the ratio.

6 0
3 years ago
How many pints are in 44 quarts?
bezimeni [28]

In 44 liquid quarts, there are 88 liquid pints. 2 pints per 1 quart. Hope this helps ;)

4 0
3 years ago
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