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iVinArrow [24]
3 years ago
10

Which statement is true of the function f(x) = -3^sqrt x ? Select three options.

Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

b,c,d

Step-by-step explanation:

Just took the test

Alenkasestr [34]3 years ago
7 0

Do you mean f(x)=-3^{\sqrt x}, as in the negative of 3 to the power of √<em>x</em> ? Or f(x)=-\sqrt[3]{x}, as in the negative cube root of <em>x </em>?

If you mean f(x)=-3^{\sqrt x}, then, going through each option:

• no: the square root component is defined only for <em>x</em> ≥ 0, for which we have √<em>x</em> ≥ 0 and hence <em>f(x)</em> < 0 for all <em>x</em> in the domain. √<em>x</em> is an increasing function, so the powers of 3 get successively larger, so <em>f(x)</em> would be always decreasing;

• no: as mentioned above, the domain would be all non-negative numbers;

• no: at minimum, <em>x</em> = 0 which gives <em>f</em> (0) = -3⁰ = -1, and because <em>f(x)</em> is decreasing over its entire domain, the range would be {<em>y</em> | <em>y</em> ≤ -1};

• no: again, a bit of ambiguity, but assuming you mean to say here y=3^{\sqrt x}, yes, <em>f(x)</em> would be a reflection of <em>y</em> across the <em>x</em>-axis;

• and finally, no: f(3)=-3^{\sqrt3}\approx-6.705

so that only the fourth option would be true.

On the other hand, if you mean f(x)=-\sqrt[3]{x}, then:

• no: the function is always decreasing;

• yes: the domain is all real numbers;

• yes: the range is {<em>y</em> | -∞ < <em>y</em> < ∞};

• yes: <em>f(x)</em> is a reflection of <em>y</em>=∛<em>x</em>, also about the <em>x</em>-axis; and

• no: <em>f</em> (3) = -∛3 ≈ -1.442

I suspect you mean the second case, since it's a bit simpler to approach.

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