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denis-greek [22]
3 years ago
6

. Первый мастер может выполнить задание,

Mathematics
1 answer:
Pavel [41]3 years ago
8 0
1 and 6 percent off my head
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Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
xxTIMURxx [149]
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\
5=\sqrt{(-1-2)^2+(-2-y_1)^2}\\
\sqrt{9+4+4y_1+y_1^2}=5\\
y_1^2+4y_1+13=25\\
y_1^2+4y_1-12=0\\
y_1^2+6y_1-2y_1-12=0\\
y_1(y_1+6)-2(y_1+6)=0\\
(y_1-2)(y_1+6)=0\\
y_1=2 \vee y_1=-6\\\\
\boxed{(2,2),(-6,2)}


3 0
4 years ago
Solve the system of equations by substitution. 3/8x + 1/3y = 17/24
VashaNatasha [74]

Answer:

this question is not complete. need another equation

Step-by-step explanation:

give another equation then I can solve

\frac{3}{8} x =  \frac{17}{24}  -  \frac{1}{3} y \\ x =  \frac{17}{9}  -  \frac{8}{9} y

7 0
3 years ago
HELP ASAP!!! WILL MARK BRAINLIEST A proportional relationship between the number of pounds of potatoes (x) and the price in doll
Snezhnost [94]

Answer:

with proportional relationships, you can simply divide the y coordinate by the x coordinate to find the unit rate: In this case, if (5,4) lies on the line then you have 5 lbs of potatoes for 4 dollars or .80 cents for 1lb of potatoes. The point (10,8) represents 10 lbs of potatoes for 8 dollars. Here you can see that dividing 8 by 10 we once again get the unit rate of .80 cents per 1 lb of potatoes.

x = lbs of potatoes and y = price(4,3)....this means 4 lbs of potatoes cost $ 33/4 = 0.75 cents per lb <== 1 lb of potatoes cost 0.75(8,6)...this means that 8 lbs of potatoes cost $ 6

Hope this helps

-Agarvated Team


4 0
3 years ago
Read 2 more answers
You would like put up a fence around your rectangular backyard. You know that the length of your backyard
Bogdan [553]

Answer:

<h2><em><u>$1,008.........................................................</u></em></h2>
3 0
3 years ago
Find the difference and simplify.
Murrr4er [49]

Step-by-step explanation:

\frac{x + 1}{x - 4}  -  \frac{x + 3}{x + 2}  \\  \frac{(x + 1)(x + 2)}{(x - 4)(x + 2)}  -  \frac{(x + 3)(x - 4)}{(x + 2)(x - 4)}  \\  \frac{ {x}^{2} + 3x + 2 }{(x + 2)(x - 4)}  -  \frac{ {x}^{2} - x - 12 }{(x + 2)(x - 4)}  \\  \frac{( {x}^{2}  + 3x + 2) - ( {x}^{2}  - x - 12)}{(x + 2)(x - 4)}  \\  \frac{ {x}^{2}  + 3x + 2 -  {x}^{2}  + x + 12}{(x + 2)(x - 4)}  \\  \frac{4x + 14}{(x + 2)(x - 4)}  \\  \frac{2(2x + 7)}{(x + 2)(x - 4)}

6 0
3 years ago
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