Answer:
Respiration
Explanation:
cross off Photosynthesis because that is specifically for plants. Diffusion is when molecules move from high concentration to low concentrations. Osmosis helps transport water across the cell.
By process of reduction you can figure it out, but here is what cellular respiration is in it's basics so you can remember in the future. Cellular Respiration is just the process that takes place in cells to convert Chemical Energy from nutrients and turn it into ATP, then releases waste.
Explanation:
Saliva contains special enzymes that help digest the starches in your food. An enzyme called amylase breaks down starches (complex carbohydrates) into sugars, which your body can more easily absorb. Saliva also contains an enzyme called lingual lipase, which breaks down fats.
Energy moves from one trophic level to another as organisms feed on one another.
Explanation:
Energy flows from one trophic level to another in a food chain. according to the ten percent law, only ten percent of the total energy passes onto the next trophic level. While studying the energy flow model two aspects should be taken under consideration. Firstly, the flow of energy is unidirectional and passes on from autotrophs to primary consumer and then secontary, tertiary so on. Secondly the amount of energy decreases at succesive trophic level.
Introns because they are coding sequences.
Exons because they are non-coding sequences.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
