Geometry class (need help)

Find the intervals of DECREASING only and write in below in interval notation.

Grace [21]

Answer:

(-1,0)

Step-by-step explanation:

It is decreasing when the "slope" of the function is negative. That only happens on the blue curve from x = -1 to x = 0. In interval notation, that's (-1,0)

8 0

3 years ago

5. Choose the fragment which best completes the following sentence. Finance charges on a credit card Include (2 points)

lisabon 2012 [21]

Finance charges on a credit card Include "all of the above".

Option: D

Explanation:

Practically, a finance charge is any expense shown in the borrowing money costs, such as accrued interest and loan fees, including transaction fees. Finance charges are usually synonymous with "interest charges" even though they may contain late fees or other costs in some situations.

With credit cards, the interest that has accrued over the amount one owe throughout that particular billing cycle is an individual's finance fee. For every day of the month, the regular balance approach sums up an individual's financing fee. One need to know the precise credit card balance every day of the billing cycle to do that estimate correctly.

7 0

4 years ago

Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o

umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)

1/2 ∫▒(2xdx/u) =1/2 ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2 ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C (required soultion)

3 0

3 years ago

Read 2 more answers

Please help me to solve these questions as soon as possible. Thank you

densk [106]

Answer:

499

9

April 12 2021

Step-by-step explanation:

1 and 500 are the smallest and largest

12 is the highest common factor

Every 12 days they have an appointment together

8 0

3 years ago

Jasper has an annual salary of $71000 and his company pays him twice a month. What is the gross income per paycheck that Jasper

Sliva [168]

Answer:

$2,958.33

Step-by-step explanation:

Jasper's annual salary is $71000.

Considering that a year has 12 months and that he gets a paycheck twice each month, the total number of paychecks (P) Jasper gets each year is:

$P = 12*2 = 24$

To define Jasper's gross income per paycheck (I), simply divide his annual salary by the number of paychecks in a year:

$I=\frac{\$ 71,000}{24} \\I=\$ 2,958.33$

Jasper's gross income per paycheck is $2,958.33.

3 0

3 years ago