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allsm [11]
3 years ago
10

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume

that the population does not exhibit a normal distribution. Weight lost on a diet:
99 % confidence
n equals 41
x overbar equals 4.0 kg
s equals 6.1 kg
Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer: (1.55, 6.45)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline\ {x}\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=41

Sample mean : \overline{x}=4.0\text{ kg}

Standard deviation : \sigma=6.1\text{ kg}

Then, 99% confidence interval for population mean will be :_

4\pm\ (2.576)\dfrac{6.1}{\sqrt{41}}\\\\\approx4\pm2.45\\\\=(4-2.45, 4+2.45)=(1.55, 6.45)

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