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Sergio [31]
2 years ago
7

Q is the midpoint for the points S(11, -6) and T(-1, 10). Find the length of segment QT. QT=

Mathematics
1 answer:
iris [78.8K]2 years ago
3 0

Answer:

10

Step-by-step explanation:

QT=ST/2=√(12^2+16^2)/2=10

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For your friend's birthday, you have 3 presents to wrap. Find the combined surface area of these 3 gifts so you know how much wr
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The answer is: 5,614 square inches.

The explanation is shown below:

1. The gift on the bottom is a rectangular prism. To calculate its surface area, you must apply the following formula:

 SA=2[(l)(w)+(l)(h)+(h)(w)]

Where l is the length (20 inches), w is the width (42 inches) and h is the heigth (16 inches).

2. Substitute values:

SA1=2[(20in)(42in)+(20in)(16in)+(16in)(42in)]=3,664in^{2

3. The surface area of the other gifts can be calculated with the formula for calculate the surface area of a cube:

SA=6s^{2}

Where s is the side.

4. The surface area of the bigger cube is:

SA2=6(15in^{2})=1,350in^{2}

5. The surface area of the smaller cube is:

SA3=6(10in^{2})=600in^{2}

6. The total surface area (the combined surface area of the three gifts) is:

SAt=SA1+SA2+SA3\\SAt=3,664in^{2}+1,350in^{2}+600in^{2}\\SAt=5,614in^{2}

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Step-by-step explanation:

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The midpoints of an irregular quadrilateral ABCD are connected to form another quadrilateral inside ABCD. Complete the explanati
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Answer:

Suppose: M, N, P, Q are the midpoints of AB, BC, CD, AD respectively

=> MNPQ is the quadrilateral inside ABCD

connect B to D, ΔABD has : M is the midpoint of AB

                                              Q is the midpoint of AD

=> MQ is the midpoint polygon of ΔABD

=> MQ // BD and MQ = 1/2.BD (1)

ΔBCD has: N is the midpoint of BC

                  P is the midpoint of DC

=> NP is the midpoint polygon of ΔBCD

=> NP // BD and NP = 1/2.BD    (2)

from (1) and (2) => MQ // NP ( //BD)

                            MQ = NP  (=1/2.BD)

=> MNPQ is a parallelogram.​

=>  the quadrilateral inside ABCD is a parallelogram.​

Step-by-step explanation:

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