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Zanzabum
3 years ago
8

The blue dot is at what value on the number line?

Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Answer:

0

Step-by-step explanation:

-10 -8 -6 -4 -2 0

g100num [7]3 years ago
5 0

Answer:

0

You go up by 2 every jump so if you start from 6 and jump 3 times it makes 3 x 2 = 6 so it cancels out the negative 6 leaving nothing or zero.

Step-by-step explanation:

You might be interested in
Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute
Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so \mu = 35

Variance = 81. The standard deviation is the square root of the variance, so \sigma = \sqrt{81} = 9.

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, z = -0.44 has a pvalue of 0.333. So what is the value of X when z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{X - 35}{9}

X - 35 = -3.96

X = 31.04

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

P = P_{1} + P_{2}

P_{1} is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of X = 40.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 35}{9}

Z = 0.61

Z = 0.61 has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if P_{1} = 100% - 72.91% = 27.09% = 0.2709

P_{2} is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

X = 38.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{38.5 - 35}{9}

Z = 0.39

Z = 0.39 has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if P_{1} = 100% - 65.17% = 34.83% = 0.3483

So:

P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0
3 years ago
Bridget needs an actor. Actor A is offering her services for an initial $250 in addition
Neporo4naja [7]
\textit{Actor A charges 250 plus 50 per day}
\\ \quad \\

\begin{array}{llll}
days&charge
\\---&---\\
1&50\cdot 1\\
2&50\cdot 2\\
3&50\cdot 3\\
4&50\cdot 4\\
d&50\cdot x\implies 50d
\end{array}\quad meaning\implies A=250+50d

\textit{Actor B charges 2500 plus 60 per day}
\\ \quad \\
\begin{array}{llll}
days&charge
\\---&---\\
1&60\cdot 1\\
2&60\cdot 2\\
3&60\cdot 3\\
4&60\cdot 4\\
d&60\cdot x\implies 60d
\end{array}\quad meaning\implies B=200+60d
\\ \quad \\
when\ is A=B?\qquad well
\\ \quad \\

250+50d\quad =\quad 200+60d\impliedby \textit{solve for days "d"}
3 0
3 years ago
To solve a problem, we often _________ the given information into algebraic expressions and equations.
bulgar [2K]
\frac{-b\pm\sqrt{b^2-4ac}}{4a}
4 0
3 years ago
What is C/a + 4 when a=2, and c= 10
tigry1 [53]

Answer:

4 and 10/2 so actually 9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Harriet has 3 crates of watermelons. Each crate alone weighs 15.5 pounds and contains between 32 and 36 watermelons. The weight
Anuta_ua [19.1K]

Answer:no

Step-by-step explanation: Each crate is 15.5 pounds there is only 3 crates therefor 3 crates weighing 15.5 pounds each would only weigh 46.5 pounds all together

4 0
3 years ago
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