AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
<span>Line AB is tangent to circle O at A</span>
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴ OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28
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I think the correct answer among the choices listed above is option C. The only true statement is that t<span>he domain of the logarithmic function f(x) = log5x is all positive real numbers. Hope this answers the question. Have a nice day.</span>
Answer:
Step-by-step explanation:
we have
If f(x) is shifted 2 units to the right
then
The rule of the translation is
so
