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jok3333 [9.3K]
4 years ago
15

5.3 divided by 37.63

Mathematics
2 answers:
Ann [662]4 years ago
6 0
7.1 is the correct answer
rodikova [14]4 years ago
4 0
0.1408450704 That is the answer.
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Hich measure of the center should he report as the "average" salary of major league players?
Bond [772]

Answer:

Mean

Step-by-step explanation:

To calculate the mean you have to sum the values and then divide them by the number of values; for example, if you have 1 and 10, the mean will be 1+10 = 11, then 11/2 = 5.5, the mean is 5.5. The mean is affected by the highest value. If we continue summing high values, the mean will go grow, for example, if you have 1, 10, 10, the mean will be, 1+10+10 = 21 then 21/3 = 7. The mean is 7, and it is closer to 10 than 1.

As the reporter wants to show they are overpaid, the mean will give a number that its affected by the highest value, in this case, the player with a higher salary.

5 0
4 years ago
. Are the triangles similar and if so why? What is the value of x? Show your work. Answer:
alexdok [17]

Answer:

  yes; x=7

Step-by-step explanation:

When two corresponding angles are congruent, all angles are congruent, so the triangles are similar. The sides of the triangle on the right are 30/25 = 6/5 times the length of the sides of the left triangle, so side MP will be 6/5 times the length of JL, or (6/5)·20 = 24.

Then the expression for that length lets us find the value of x:

  24 = 4x -4

  6 = x -1 . . . . . divide by 4

  7 = x . . . . . . . add 1

5 0
4 years ago
Can someone get this for me for 50 points?!?!<br> I really need help!!
STALIN [3.7K]

Answer:

{ ({x}^{ \frac{1}{6} } )}^{9}  \times  \sqrt[6]{ {x}^{9} }  \\  {(x)}^{ \frac{9}{6} } \times  {(x)}^{ \frac{9}{6}} \\  {(x)}^{ \frac{3}{2} }  \times  {(x)}^{ \frac{3}{2} }  \\{(x)}^{ (\frac{3}{2} +  \frac{3}{2})}  \\  {(x)}^{ \frac{(3 + 3)}{2}}\\{(x)}^{ (\frac{6}{2})}  \\\boxed{{x}^{3}}✓

<h3><u>x³</u> is the right answer.</h3>
8 0
3 years ago
I need help 2(x + 1) = 2x + 2.
Ksju [112]
2(x + 1) = 2x + 2\\&#10;2x+2=2x+2\\&#10;0=0\\&#10;x\in\mathbb{R}
7 0
3 years ago
If f(x)=x squared-2x and g(x) = 6x+4 for which is a value of x does (f+g)(x) =0
ra1l [238]

Answer:

For x = -2

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

f(x) = x^2 - 2x

g(x) = 6x + 4

f(x) + g(x) = (f+g)(x)  = x^2 - 2x + 6x + 4 = x^2 + 4x + 4

Which is a value of x does (f+g)(x) =0

x^2 + 4x + 4

Quadratic equation with a = 1, b = 4, c = 4

So

\Delta = 4^{2} - 4*1*4 = 0

x_{1} = \frac{-4 + \sqrt{0}}{2} = -2

x_{2} = \frac{-4 - \sqrt{0}}{2} = -2

For x = -2

7 0
3 years ago
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