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Margarita [4]
3 years ago
5

If f(x)=x squared-2x and g(x) = 6x+4 for which is a value of x does (f+g)(x) =0

Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

For x = -2

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

f(x) = x^2 - 2x

g(x) = 6x + 4

f(x) + g(x) = (f+g)(x)  = x^2 - 2x + 6x + 4 = x^2 + 4x + 4

Which is a value of x does (f+g)(x) =0

x^2 + 4x + 4

Quadratic equation with a = 1, b = 4, c = 4

So

\Delta = 4^{2} - 4*1*4 = 0

x_{1} = \frac{-4 + \sqrt{0}}{2} = -2

x_{2} = \frac{-4 - \sqrt{0}}{2} = -2

For x = -2

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