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2 years ago

Find the slope of line that is parallel to -2x=3y+5

Mathematics

1 answer:

In-s [12.5K]2 years ago

7 0

Answer: m = $-\frac{2}{3}$

Step-by-step explanation:

Turn the equation into slope-intercept form: $-3y = 2x + 5$

Reduce: $y = -\frac{2}{3}x -\frac{5}{3}$

Your parallel slope is: $-\frac{2}{3}$

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72 inches=___ yards please and thank you for your help

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We know that:

$1yd=36in\text{.}$

Then:

$1in=\frac{1}{36}yd\text{.}$

Therefore:

$72in=72\cdot(\frac{1}{36}yd)\text{.}$

Simplifying the above result we get:

$72\cdot\frac{1}{36}yd=2yd\text{.}$

Answer:

$72\text{inches}=2\text{yards.}$

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2 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

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2 years ago