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kipiarov [429]
2 years ago
5

A projectile is thrown upward off a 130ft cliff at a velocity of 15ft/second. How long before it reaches a height of 25ft?

Mathematics
1 answer:
zhuklara [117]2 years ago
5 0

Answer:

The time taken for the projectile to reach the given height is 1.2 s.

Step-by-step explanation:

Given;

height of travel, h = 25 ft

initial velocity of the projectile, u = 15 ft/s

The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;

h = ut + ¹/₂gt²

25 = 15t + ¹/₂(9.8)t²

25 = 15t + 4.9t²

4.9t² + 15t - 25 = 0

solving the quadratic equation, we will have the following solution of t;

t = 1.2 s

Therefore, the time taken for the projectile to reach the given height is 1.2 s.

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Step-by-step explanation:

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2 years ago
What's the answer to: divide £48 in the ratio 7:5 (please show your working, much appreciated)
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I can see you come from outside the USA. No insults intended!!
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Anyways, we have to put one side of the ratio and match it to 48. 
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Or even better...
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MAKE!!
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So... Let's say 7 is proportional to 48... so 7/5 = 48/x, where x is the number equivalent to ratio of 5.
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3 years ago
Which of the following shows the length of the third side, in inches, of the triangle below? (1 point)
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