The total price is $12.38. First you multiply $14.00 x .15 which equals $2.10. Then you subtract $2.10 from $14.00 which equals $11.90. The next step is to multiple $11.90 x . 04 which equals $0.48. Then you add $11.90 + $0.48 which equals $12.38.
Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80
Answer:
remember to read carefully
Step-by-step explanation:
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Step-by-step explanation:
