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3 years ago

SOMEONE HELPPPP IS THIS ONE CORRECT?

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

YES ITS CORRECT GOOD JOB

Korolek [52]3 years ago

3 0

Answer:

yea

Step-by-step explanation:

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Given tanθ = 8, find csc(θ)

In-s [12.5K]

Cosecθ=sq.rt of 65/8. hope it will help you

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3 years ago

Read 2 more answers

ruslelena [56]

I need more information to answer this question.

8 0

3 years ago

Andrew has already played 32 minutes on his video game today and wants to play an additional 15 minutes each of x games after sc

artcher [175]

Answer:

y = 15x+32

Step-by-step explanation:

Given

y to be the total minutes Andrew will play video games today

x is the total number of games played after school

If he wants to play an additional 15 minutes each of x games after school today, the total minutes he will use for the x games will be 15* x = (15x)minutes

We are told that he has initially spent 32minutes on video games. hence;

Total minutes Andrew used on games y = (15*x)+32

The required equation will be y = 15x+32

7 0

3 years ago

Tickets to a football final are selling well. On Thursday, 47 of the tickets are sold. On Friday, 14 of the tickets are sold. Wh

lbvjy [14]

The question seems incomplete ; as the total number of tickets to be sold isn't given.

Answer:

61 / X

Step-by-step explanation:

Let's take the total Number of tickets to be sold as : X

Number of tickets sold on Thursday = 47

Number sold on Friday = 14

Fraction of tickets available for sale on Saturday :

(Total number of tickets already sold) / Total number of tickets to be sold

(Thursday + Friday sales) / total number of tickets to be sold

Fraction available for sale on Saturday = (47+14) / X

Fraction available for sale on Saturday = 61 / X

Kindly put value of x = total number of tickets available for sale to get the exact fraction.

6 0

3 years ago

A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i

yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

$T - Ts = (T_0 - Ts)e^k^t$

We'll solve for k

$35 - 100 = (20 - 100)e^9^k$

$-65 = (-80)e^9^k$

Divide both sides by -5

$13 = (16)e^9^k$

$9k = ln (\frac{13}{16})$

$k = \frac{1}{9} ln (\frac{13}{16})$

$k = -0.02307104053$

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

$T - Ts = (T_0 - Ts)e^k^t$

$T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100= -52.8125$

$T = 100 - 52.8125$

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0

3 years ago