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KonstantinChe [14]
3 years ago
13

What is 7 times 3 + 8

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

29

Step-by-step explanation:

7 times 3 = 21 + 8= 29

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Which revolution will generate this hemisphere?
andrey2020 [161]

Answer:

Rotate a semicircle 180° about its diameter

Step-by-step explanation:

For common figures, the shape of a figure that revolves about a line which is at the base of the figure to give a 3 dimensional shape is the shape of the cross section of the 3 dimensional figure when the angle of revolution is 180° and half the shape of the cross section of the formed 3 dimensional figure, when the angle of revolution is 360°

The cross section of an hemisphere is a semicircle, therefore, the shape of an hemisphere is formed by rotating a semicircle 180° about the diameter (which is the straight line at the "base") of the semicircle

Therefore;

The correct option that gives the revolution that will generate the hemisphere is;

Rotate a semicircle 180° about its diameter.

5 0
3 years ago
. How long is 50% of 30 minutes?
BlackZzzverrR [31]

Answer:

The answer is 15 minutes

Step-by-step explanation:

Hope this helps :)

have a nice day and could i have brainliest plz? :)

8 0
3 years ago
Read 2 more answers
Please help I don’t understand how to do these
steposvetlana [31]

Answer:

I think there would be 86 blue marbles

x=4(106 - x ) + 6

x= 424 - 4x + 6

5x= 430

x= 86 blue marbles

Tell me if I'm wrong, hope this helps.

3 0
3 years ago
How many ounces of yogurt can you get<br> for $4.00?
Olenka [21]
It depends how much each pound is
6 0
4 years ago
5. In the diagram shown below, BC is drawn tangent
Tatiana [17]

9514 1404 393

Answer:

 (2)  72°

Step-by-step explanation:

In this geometry, the angle at the tangent is half the measure of the intercepted arc.

  ∠CBD = (arc BD)/2 = 144°/2

  ∠CBD = 72°

__

<em>Additional comment</em>

Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.

As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.

6 0
3 years ago
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