Question

A line passes through tge points (1,-3) and (4,6) what is the zero of this line ?

Answer 1

Answer:

The zero of the line is (2,0)

Step-by-step explanation:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as:

$\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

We are given the points (1,-3) and (4,6). Substituting:

$\displaystyle y+3=\frac{6+3}{4-1}(x-1)$

Operating:

$\displaystyle y+3=\frac{9}{3}(x-1)$

$y+3=3(x-1)$

The zero of this line can be found by making y=0 and solving for x:

0+3=3(x-1)

3=3x-3

Adding 3:

6=3x

Solving:

x = 2

The zero of the line is (2,0)