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3 years ago

7x+8y= 8 Slope Y intercept

Mathematics

2 answers:

lana [24]3 years ago

6 0

Answer:

$slope = - \frac{7}{8}$

y- intercept= 1

Step-by-step explanation:

Rearrange the equation such that it is in the form of y=mx+c. This form is known as the slope-intercept form, and m is the gradient while c is the y-intercept.

7x +8y= 8

8y= -7x +8

Divide by 8 on both sides:

$y = - \frac{7}{8} x + 1$

Thus, the slope is $- \frac{7}{8}$ and the y-intercept is 1.

Another way to find the y-intercept is to substitute x= 0 into the equation since the y-intercept occurs at x= 0.

7x +8y= 8

When x= 0,

7(0) +8y= 8

8y= 8

y= 8 ÷8

y= 1

Thus, the y-intercept occurs at y= 1 or the coordinate (0, 1).

Note: slope and gradient have the same meaning and can be used interchangeably

Cloud [144]3 years ago

3 0

Answer:

Slope = -7/8

Y-intercept = (0, 1)

Step-by-step explanation:

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Step-by-step explanation:

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Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

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3 years ago

I need Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

quester [9]

9514 1404 393

Answer:

150.72 cm³
314 cm³
160 cm³
48 cm³

Step-by-step explanation:

Put the given numbers in the relevant formula and do the arithmetic.

right cylinder

V = πr²h = 3.14(4 cm)²(3 cm) = 3.14×48 cm³ = 150.72 cm³

cone

V = 1/3πr²h = 1/3(3.14)(5 cm)²(12 cm) = 3.14×100 cm³ = 314 cm³

pyramid of unknown shape

V = 1/3Bh = 1/3(16 cm²)(30 cm) = 160 cm³

square pyramid

V = 1/3s²h = 1/3(3 cm)²(16 cm) = 48 cm³

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3 years ago