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elixir [45]
2 years ago
15

Given the expression 5a2b2 − 13ab + 7a3 − 4b, do the following as instructed below:

Mathematics
1 answer:
ozzi2 years ago
8 0
1. descending order (greatest to least): 7a3+5a2b-4b-13ab
2. classification: 4 terms
3. the degree: 3
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the radius of a cylindrical construction pipe is 2 ft. If the pipe is 26 ft long, what is its volume?
Mamont248 [21]
Thxr2x26=

3.14x2x2x26= 326.56 ft3
6 0
3 years ago
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Select all the equations where x = 3 is a solution.
34kurt

Answer:

Step-by-step explanation:

X +4=

8x=32

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3 years ago
Anthony buys one pound of oranges for $12 and sells it for $14. How can he write the profit in his account book?
Aleonysh [2.5K]
The answer would be, A) +$2 because he spend $12 but earned $14 so when you subtract 14 and 12 you get $2, which would be his profit
5 0
3 years ago
Prove that tan60+tan70-tan50+tan10=2sqrt3?
LiRa [457]
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)} 

<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>

<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>

<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>

<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>

<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
8 0
3 years ago
Grumpy Corp drug tests all of the recent college graduates it hires each year. The drug test currently used correctly determines
Vedmedyk [2.9K]

Answer:

Hence, the probability of a Negative test is P(T^C)=0.5904.

Step-by-step explanation:

(a)

Let D= Drug user and T= Test positive

Probability of drug users P(D)=36\%=0.36

                                    P(\frac{T}{D})=96\%=0.96

                                   P(\frac{T^c}{D^c})=90\%=0.90

(b)

Find the Probability of a Negative test,

     P(T^C)=P(\frac{T^C}{D^C})\cdot P(D^C)+P(\frac{T^C}{D})\cdot P(D)

\Rightarrow P(T^C)=0.9\cdot(1-0.36)+(1-0.96)\cdot 0.36

\Rightarrow P(T^C)=0.9\cdot 0.64+0.04\cdot 0.36

\Rightarrow P(T^C)=0.576+0.0144

\Rightarrow P(T^C)=0.5904

4 0
3 years ago
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