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Blizzard [7]
3 years ago
13

What is the slope intercept form of y + 1 = -2 (x-1)?

Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

The eqaution y + 1 = -2 (x-1) in slope intercept form is

y = -2x - 3

Step-by-step explanation:

Write in slope-intercept form, y = mx + b

Mars2501 [29]3 years ago
4 0
Y+1 = -2x+2 (distribute)
Y=-2x + 1 (isolate y)
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Step-by-step explanation:

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2 years ago
A basket contains 20 green apples and 30 red apples. If a piece of fruit is selected at random from the basket, what is the prob
Dmitrij [34]

Answer:

40%

Step-by-step explanation:

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4 0
3 years ago
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3 years ago
Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
3 years ago
How do I solve this problem??
choli [55]
They're the same like integers.
First you should interpret it.
For example:
a. -3x + 8x is the same like -3 + 8. You just add x.
Which is 5x.
3 0
3 years ago
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