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3 years ago

The radius of a cylindrical water tank is 4.5 ft, and its height is 8 ft. What is the volume of the tank?

1 answer:

4 0

Use the value 3.14 for it, and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
15 . Mark me brainliest !!

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sukhopar [10]

They live 9 3/4 blocks away from eachother

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3 years ago

Read 2 more answers

Which of the following expressions is the conjugate of a complex number with −5 as the real part and 4i as the imaginary part? 5

ladessa [460]

The mathematical expression of the given complex number above is -5 + 4i. The conjugate of this complex number is that which has an opposite operation. The given is an addition operation. That is -5 - 4i. Therefore, the answer is the third among the choices.

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3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

Let x be the price of a new car. Let n be the number of people willing to buy the car at price x. As the price of the car goes f

Ostrovityanka [42]

As the price of the car increases, the number of people
willing to buy it decreases.

The line in the first graph ' A ' is doing that.

4 0

3 years ago

When distributing how would i go about. distributing and variable plus a constanat term????

kozerog [31]

Answer:

3c+4

Step-by-step explanation:

When distributing a problem with 2 of the same signs, all you have to do is leave it the way it is. Basically pretend it's not there at all and you should the answer

4 0

3 years ago