Help plz ill give extra points
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So hmm check the picture below
a circle has a total of 360°, thus arcBC + x + arcCD is 360, so arcCD is just 360 - 112 - x, whatever "x" was that you found
a circle has a total of 360°, thus arcBC + x + arcCD is 360, so arcCD is just 360 - 112 - x, whatever "x" was that you found
x = 32°
The triangle has 2 equal sides and is therefore isosceles, thus the 2 base angles are also congruent.
The 2 base angles are of size x°
x = =
= 32