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2 years ago

A sculptor needs to lift a piece of marble.

Mathematics

2 answers:

Vladimir79 [104]2 years ago

6 0

Answer:

486 kg

Step-by-step explanation:

Dennis_Churaev [7]2 years ago

4 0

Answer:

486kg

Step-by-step explanation:

density = mass / volume

2.7 = m / (100 x 60 x 30) **** Note the conversion to cm as the density is given in g/cm.

2.7 = m / 180000

m = 486000g

Now convert to mass in kg:

486000 g x 1 kg / 1000 g = 486kg

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Write the following number in standard decimal form. seven and sixty-one thousandths

amid [387]

Answer:

0.761

Step-by-step explanation:the 7 is in the tenths the 6 is in the hundredths and the 1 is in the thousandths

4 0

2 years ago

what is the probability that a randomly chosen number is less than or equal to 90 and is a multiple of 17

kodGreya [7K]

Answer:

let's see...

we have total possible outcomes.. = 90 ( from 1 to 90)

Desiree outcomes..= 5 ( 17,34,51,68,85)

and therefore.. the probability is 5/90 = 1/18.

here you go.. that should be correct I hope.

3 0

2 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

A young women walked into a cafe and asked for a drink of water the man behind the counter suddenly pulled out a gun and pointed

dexar [7]

Did you write this??

Thank you for sharing

7 0

2 years ago

Order least to greatest 1/2, 0.55, 5/7

Nataliya [291]

1/2<0.55<5/7
This is the order from least to greatest

8 0

3 years ago

Read 2 more answers