Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
Answer:
x=6.42
Step-by-step explanation:
Multiply both sides by 5.35.
x=1.2×5.35
Simplify 1.2×5.35 to 6.42.
x=6.42
Answer:
∠ ABD = 42°
Step-by-step explanation:
∠ ODC = 90° ( angle between tangent and radius )
∠ ADC = 90° - 48° = 42°
The angle between a tangent and a chord is equal to the angle in the alternate segment, that is
∠ ABD = ∠ ADC = 42°
To approximate the distance of points with three dimension, make use of the equation,
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2 +(z2 - z1)^2)
Substituting all the data from the points given,
<span>d = sqrt ((2 - -2)^2 + (-7 - 3)^2 +(4 - -5)^2) = sqrt 197
</span>
Thus, the distance from the points is approximately 14.04 and that is letter D.
Step-by-step explanation:
We have,
Mass of ball is 9 kg
Initial speed, u = 5 m/s
Final speed, v = -2 m/s (negative as it bounces off)
(a) The change in velocity of the bowling ball is :
(b) Change of momentum of the ball is :
|p| = 630 kg-m/s
(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.
(d) Impulse is also given by :
