The two lines graphed on the coordinate grid each represent an
1 answer:
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Answer:
E is not a subspace of
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
Answer:
Step-by-step explanation:
Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.
a) P(E) = P(the difference of the numbers is 3 or more}
Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)
P(E) =
b)P(F)
Favourable events for F = (1,1) (2,2)...(6,6)
P(F) =
c) P(EF)
There is no common element between E and F
P(EF) =0