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WINSTONCH [101]
3 years ago
7

Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance

and time according to this function v(t,x) = x/t. Your measured distance and time have the following values and uncertainties x = 8.1 meters, Δx = 0.9 meters and t = 1.7 seconds and Δt = 1.7 seconds. What is the uncertainty in the average speed, Δv ?
Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

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A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
stealth61 [152]

Answer:

a) On this case we are interested on the population proportion of students that have a GPA of 3.00 or below.

b) z=\frac{0.15 -0.2}{\sqrt{\frac{0.2(1-0.2)}{200}}}=-1.77  

p_v =P(z  

c) Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

d) The significance level provided is \alpha=0.05. If we compare the  p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the population proportion of students that have a GPA of 3.00 or below is significantly lower than 0.2.  

Step-by-step explanation:

Data given and notation n  

n=200 represent the random sample taken

X=30 represent the  students with a GPA of 3.00 or below.

\hat p=\frac{30}{200}=0.15 estimated proportion of  students with a GPA of 3.00 or below.  

p_o=0.2 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

a. In testing the university's belief, how does on define the population parameter of interest?

On this case we are interested on the population proportion of students that have a GPA of 3.00 or below.

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of graduates with GPA of 3.00 or below is less than 0.2.:  

Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

b. The value of the test statistics and its associated p-value are?

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.15 -0.2}{\sqrt{\frac{0.2(1-0.2)}{200}}}=-1.77  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

Since is a one left tailed test the p value would be:  

p_v =P(z  

c. In testing the university's belief, the appropriate hypothesis are?

Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

d. At a 5% significance level, the decision is to?

The significance level provided is \alpha=0.05. If we compare the  p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the population proportion of students that have a GPA of 3.00 or below is significantly lower than 0.2.  

5 0
3 years ago
in the 1980s, an average mortgage range was around 18.75%. how much less per month would a $125,000 30 year mortgage be today if
tino4ka555 [31]

Answer:

  $1289.48

Step-by-step explanation:

A financial calculator tells you the payment with the higher interest rate is $1960.51, and that with the lower interest rate is $671.03. The difference in payment amounts is ...

  $1960.51 -671.03 = $1289.48

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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