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STALIN [3.7K]
3 years ago
5

What is the value of x? Round to the nearest tenth

Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Answer:

x = 8

Hope this helps!

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The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area
Natasha2012 [34]
L=w+2 and 2w+2l=44

substitute equation for length in perimeter equation

2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10

substitute width into length equation to get length

l=10+2
l=12

a=lw
a=12*10
a=120 cm^2
7 0
3 years ago
Please select the best answer and click submit Solve kx-4=9 for x
shepuryov [24]

Answer:

Option B. x = \frac{13}{k}.

Step-by-step explanation:

The given equation is kx - 4 = 9

We will add 4 on both the sides of the equation

kx - 4 +4 = 9 +4

kx = 13

Now we will divide by k on both the sides of the equation

\frac{1}{k}(13x) = \frac{1}{k}13

x = \frac{13}{k}

Therefore Option B x = 13/k is the right answer.

6 0
3 years ago
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You start at (5,3) you move down 4 units and up 6 units. where do you end?
Anestetic [448]

You end up at the point (5, 5).

7 0
3 years ago
A support cable connects the top of a bridge tower to the road at a point 200.7 feet away from the center of the bridge tower
andrey2020 [161]
Helen jwhwjwj jwjwjwjw jwjwjwj where
4 0
3 years ago
60 students study a language at a school.
mixas84 [53]
  1. The number of girls is 24.
  2. The number of boys that study French is 24.
  3. The numbber of boys that study German is 12.
  4. The number of girls that study French is 16
  5. The number of girls that study German is 8.

<h3>How to fill the frequency tree?</h3>

The number of girls = total number of students - total number of boys

60 - 36  = 24

The number of boys that study French = 2/3 x 36 = 24

The numbber of boys that study German = 36 - 24 = 12

The number of girls that study French = 40 - 24 = 16

The number of girls that study German = 24 - 16 = 8

Please find attached the frequency tree. To learn more about addition, please check: brainly.com/question/349488

#SPJ1

3 0
2 years ago
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