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ludmilkaskok [199]
3 years ago
8

If tantheta -cottheta =a and costheta +sintheta =b then 4b^2(2-b^2)​

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

= 4(1+sin2theta)²

Step-by-step explanation:

Given the equations

tantheta -cottheta =a... 1

costheta +sintheta =b .... 2

We are to find 4b^2(2-b^2)​

Squaring both sides of equation 2

(costheta +sintheta)^2 = b^2

cos^2theta + 2costheta sintheta + sin^2 theta = b^2

(cos^2theta+ sin^2 theta) + 2costheta sintheta = b^2

1 + 2costheta sintheta = b^2

1 + sin2theta = b^2

substitute

4b^2(2-b^2)​

= 4(1+sin2theta)(2-1+sin2theta)

4(1+sin2theta)(1+sin2theta)

= 4(1+sin2theta)²

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Simplify the expression in picture
sergey [27]

Answer:

6x^2 + -10

Step-by-step explanation:

Hi there! I'm glad I was able to help you answer this polynomial expression!

All we're really doing to solve is combine like terms.

(5x^2+2) - (-4x^2+7) + (-3x^2-5) = _____________

5x^2 + 2 + 4x^2 + -7 + -3x^2 + -5

(5x^2 + 4x^2 + -3x^2) + (2 + -7 + -5)

6x^2 + -10

The terms that have x^2 at the end are in bold letters so you know what we're combining them - the other numbers are the separate like terms.

Simplified, our answer is 6x^2 + -10.

I hope this helped you! Leave a comment below if you have any further questions! :)

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3 years ago
Consider the function.
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Answer:

Statement 3

Step-by-step explanation:

y = -2/3x-24

Make x the subject

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Intersection variables

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No domain restrictions

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