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BARSIC [14]
3 years ago
6

Find the value of x that make it true

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

Step-by-step explanation:

1). 10 = \frac{1+7x}{7+x}

   10(7 + x) = 1 + 7x

   70 + 10x = 7x + 1

   10x - 7x = 1 - 70

   3x = -69

   x = -23

2). 0.2 = \frac{6+2x}{12+x}

    0.2(12 + x) = 6 + 2x

    2.4 + 0.2x = 6 + 2x

    2.4 - 6 = 2x - 0.2x

    1.8x = -3.6

    x = -2

3). 0.8 = \frac{x}{x+0.5}

    0.8(x + 0.5) = x

    0.8x + 0.4 = x

    x - 0.8x = 0.4

    0.2x = 0.4

    x = 2

4). 3.5 = \frac{4+2x}{0.5-x}

    3.5(0.5 - x) = 4 + 2x

    1.75 - 3.5x = 4 + 2x

    -3.5x - 2x = 4 - 1.75

    -5.5x = 2.25

     x = -\frac{2.25}{5.5}

     x = - \frac{9}{22}

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Step-by-step explanation:

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3 years ago
In the given figure find the area of the shaded region if AC = 24 CM AB = 7cm and O is the centre
wariber [46]
See the attached figure to better understand the problem

we know that

<span>The inscribed angle in a circle measures half of the arc it comprises.

</span>in this problem
the inscribed angle= ∠ACB
and the arc it comprises measures 180°
then
the ∠ACB=180°/2-------> ∠ACB=90°


<span>applying the Pythagorean theorem
</span>AC²+CB²=AB²-------> AB²=24²+7²-------> AB²=625------> AB=25 cm

the diameter of circle is AB
radius=25/2--------> r=12.5 cm

[the area of a half circle]=pi*r²/2------> pi*12.5²/2--------> 245.44 cm²

[area of triangle ABC]=AC*CB/2--------> 24*7/2-------> 84 cm²

[the area of the shaded region]=[the area of a half circle]-[area of triangle ABC]

[the area of the shaded region]=245.44-84-------> 161.44 cm²

the answer is 
the area of the shaded region is 161.44 cm²


5 0
4 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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4 0
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SVETLANKA909090 [29]
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