Answer:
22 divided 5 I would think
Step-by-step explanation:
Answer:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Step-by-step explanation:
Given the function
![f\left(x\right)=x^3-6x^2+3x+10](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3Dx%5E3-6x%5E2%2B3x%2B10)
As the highest power of the x-variable is 3 with the leading coefficients of 1.
- So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.
solving to get the zeros
![f\left(x\right)=x^3-6x^2+3x+10](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3Dx%5E3-6x%5E2%2B3x%2B10)
∵ ![f(x)=0](https://tex.z-dn.net/?f=f%28x%29%3D0)
as
![Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0](https://tex.z-dn.net/?f=Factor%5C%3Ax%5E3-6x%5E2%2B3x%2B10%5C%3A%3A%5C%3A%5Cleft%28x%2B1%5Cright%29%5Cleft%28x-2%5Cright%29%5Cleft%28x-5%5Cright%29%3D0)
so
Using the zero factor principle
if ![ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)](https://tex.z-dn.net/?f=ab%3D0%5C%3A%5Cmathrm%7Bthen%7D%5C%3Aa%3D0%5C%3A%5Cmathrm%7Bor%7D%5C%3Ab%3D0%5C%3A%5Cleft%28%5Cmathrm%7Bor%5C%3Aboth%7D%5C%3Aa%3D0%5C%3A%5Cmathrm%7Band%7D%5C%3Ab%3D0%5Cright%29)
![x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0](https://tex.z-dn.net/?f=x%2B1%3D0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax-2%3D0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax-5%3D0)
![x=-1,\:x=2,\:x=5](https://tex.z-dn.net/?f=x%3D-1%2C%5C%3Ax%3D2%2C%5C%3Ax%3D5)
Therefore, the zeros of the function are:
![x=-1,\:x=2,\:x=5](https://tex.z-dn.net/?f=x%3D-1%2C%5C%3Ax%3D2%2C%5C%3Ax%3D5)
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Therefore, the last option is true.
Answer:
3.78
Step-by-step explanation:
Answer: The distance around the lot is given by
![4\frac{1}{20}\ miles](https://tex.z-dn.net/?f=4%5Cfrac%7B1%7D%7B20%7D%5C%20miles)
Step-by-step explanation:
Since we have given that
Length of rectangular lot is given by
![1\frac{1}{8}\\\\=\frac{9}{8}\ miles](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B8%7D%5C%5C%5C%5C%3D%5Cfrac%7B9%7D%7B8%7D%5C%20miles)
Width of rectangular lot is given by
![\frac{9}{10}\ mile](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D%5C%20mile)
We need to find the distance around the lot.
As we know the formula for "Perimeter of rectangle":
![Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles](https://tex.z-dn.net/?f=Perimeter%3D2%28Length%2BWidth%29%5C%5C%5C%5CPerimeter%3D2%28%5Cfrac%7B9%7D%7B8%7D%2B%5Cfrac%7B9%7D%7B10%7D%29%5C%5C%5C%5CPerimeter%3D2%28%5Cfrac%7B45%2B36%7D%7B40%7D%29%5C%5C%5C%5CPerimeter%3D2%5Ctimes%20%5Cfrac%7B81%7D%7B40%7D%5C%5C%5C%5CPerimeter%3D%5Cfrac%7B81%7D%7B20%7D%5C%5C%5C%5CPerimeter%3D4%5Cfrac%7B1%7D%7B20%7D%5C%20miles)
Hence, the distance around the lot is given by
![4\frac{1}{20}\ miles](https://tex.z-dn.net/?f=4%5Cfrac%7B1%7D%7B20%7D%5C%20miles)
The answer is 84 degrees you just subtract 180-90