Answer:
0.073 = 7.3% probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 650 pounds and a standard deviation of 20 pounds.
This means that ![\mu = 650, \sigma = 20](https://tex.z-dn.net/?f=%5Cmu%20%3D%20650%2C%20%5Csigma%20%3D%2020)
What is the probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste?
Less than 620:
pvalue of Z when X = 620. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{620 - 650}{20}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B620%20-%20650%7D%7B20%7D)
![Z = -1.5](https://tex.z-dn.net/?f=Z%20%3D%20-1.5)
has a pvalue of 0.0668
More than 700:
1 subtracted by the pvalue of Z when X = 700. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{700 - 650}{20}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B700%20-%20650%7D%7B20%7D)
![Z = 2.5](https://tex.z-dn.net/?f=Z%20%3D%202.5)
has a pvalue of 0.9938
1 - 0.9938 = 0.0062
Total:
0.0668 + 0.0062 = 0.073
0.073 = 7.3% probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste
Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1)d]
Here, a = 6, n = 26 and d = 14 - 6 = 8
S26 = 26/2[2(6) + (26 - 1)8] = 13[12 + 25(8)] = 2,756
Answer: its 48% i took the test
Step-by-step explanation:
Answer:
222.86
Step-by-step explanation:
<h2><u>in order to solve this question you can create an equation :</u></h2>
35% * x = 78
where x is the original amount
in order to get x , you have to say :
78/ 35% = x
hence x = 222.8571...
to 2dp = 222.86