Sulphur is the element most likely responsible for methionine unique properties.
METHIONINE:
- Methionine is one of the essential amino acids in nature. Methionine is also a sulfur containing amino acid alongside cysteine.
- Generally, amino acids are structurally made up of an amino group (-NH2), a carboxyl group (-COO) and a R side chain. The R side chain differentiates each amino acid as no two amino acids possess the same side chain.
- The side chain of methionine contains sulphur, which accounts for its unique properties as an amino acid.
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Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.
Yes they can and many more
Answer:
(-) sense single-stranded RNA
Explanation:
Negative sense refers to viruses that use the negative sense single stranded RNA as their genetic material.
It is essential for the negative viral strand is complimentary to the mRNA so it is converted to a positive RNA by RNA polymerase.
Negative sense single stranded RNA virus require an RNA dependent RNA polymerase for transcription. This is because it essential in encoding proteins by catalyzing the complimentary RNA strand to the given RNA tempelate.
Answer:
Both parents are heterozygous i.e. Aa
Explanation:
This question involves a single gene coding for melanin pigmentation in humans. The dominant trait is normal pigmentation while the recessive trait is albinism. Note that, recessive trait means that both alleles must contain the same recessive alleles.
Let's say that the allele for normal pigmentation (presence of melanin) is A while the allele for albinism (without melanin) is a. The allele for normal pigmentation (A) is dominant over the allele for albinism (a). This means that allele "A" will always mask the phenotypic expression of allele "a" in a heterozygous state.
If a man and a woman with normal pigmentation gives birth to an albino child, it means the parents have the albino allele being masked in their genotype. In other words, both parents are heterozygous i.e Aa. If the two parents come together (see punnet square), gametes A and a will be produced by each parent.
The recessive alleles (a) of each parent's gamete combines to form a child that possesses the recessive trait (aa). Hence, the genotype of the parents will be HETEROZYGOUS (Aa).