Answer:
The children can have all of the following, AB, A and B.
Explanation:
Within a Punnett square, BO and AB can only make AB, Ao, BB and BO.
Answer: Liver
Glucose is the most important fuel source for the body, specifically the brain. It is absorbed through the
mucosal lining into the epithelial cells of the intestine by active transport
via sodium-dependent hexose
transporter. From the epithelial cells, glucose is moved into the surrounding capillaries
by facilitated diffusion into the liver. Once in the liver, glucose is stored as glycogen.
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>