A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathroom, kitchen, and exterior outlets is referred to as: Ground-fault interrupter.
<h3>What are
arc-fault circuit interrupter?</h3>
According to "Article 100 Arc-Fault Circuit interrupter (AFCI)," arc-fault circuit interrupter is an electrical device which is designed and developed to deenergize the electrical circuit whenever it detects and recognizes characteristics unique to arcing.
Similarly, a ground-fault interrupter simply refers to an electrical device that is designed and developed for the detection of small current differences in an electrical circuit.
The main purpose of a ground-fault interrupter is to prevent electrocution or electrical shock and as such, it is an important safety measure for the following areas in a building:
- Bathroom
- Kitchen
- Exterior outlets
Read more on ground-fault interrupter here: brainly.com/question/12615861
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Answer:
a)1815Joules b) 185Joules
Explanation:
Hooke's law states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically;
F = ke where;
F is the applied force
k is the elastic constant
e is the extension of the material
From the formula, k = F/e
F1/e1 = F2/e2
If a force of 60N causes an extension of 0.5m of the string from its equilibrium position, the elastic constant of the spring will be ;
k = 60/0.5
k = 120N/m
a) To get the work done in stretching the spring 5.5m from its position,
Work done by the spring = 1/2ke²
Given k = 120N/m, e = 5.5m
Work done = 1/2×120×5.5²
Work done = 60× 5.5²
Work done = 1815Joules
b) work done in compressing the spring 1.5m from its equilibrium position will be gotten using the same formula;
Work done = 1/2ke²
Work done =1/2× 120×1.5²
Works done = 60×1.5²
Work done = 135Joules
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