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2 years ago

What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod

Physics

1 answer:

Inga [223]2 years ago

6 0

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

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An object started at

nataly862011 [7]

Answer:

According to me, I think this is the answer

Explanation:

initial position= -22 meters.

this indicates that object is in the negative direction as a negative sign is used to represent the location.

displacement is indicated as -10.4 meters. this is also in the negative direction.

initial + displacement= final

= -22 + (-10.4)

= -32.4 meters

this would be the final position, away from the origin.

displacement is a vector quantity; both magnitude and direction matter.

5 0

3 years ago

a 1200 kg car rolling on a horizontal surfact has a speed of 25 m/s when it strikes a horizontal coiled spring and is brought ot

gizmo_the_mogwai [7]

The required spring constant:

The spring constant of the spring is $12\times 10^4 \text{ N/m}$ .

Calculation:

The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.

From the conservation of energy,

Total initial kinetic energy= Total final potential energy of the spring

Therefore,

$\frac{1}{2}mv^2=\frac{1}{2}kx^2$

Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:

$\begin{aligned}1200\times(25)^2&=k\times (2.5)^2\\\Rightarrow k&=\frac{1200\times(25)^2}{(2.5)^2}\\&=12\times 10^4 \text{ N/m}\end{aligned}$

To know more about spring constant, refer to:

brainly.com/question/14159361

#SPJ4

5 0

2 years ago

Scientific notation. jst 11a

coldgirl [10]

Answer:

2 * 10^4

Explanation:

(3 * 10^4)(4 * 10^4) / (6 * 10^4)

= (12 * 10^8)/(6 * 10^4)

= 2 * 10^4

5 0

2 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$