Answer: Memory hierarchy is the hierarchy that is created on the basis of the response time of different memories. The performance obtained by the memory helps in creating a computer storage space in distinguished form. The factors considered for the creating of the hierarchy structure are usually response time, storage capacity, complexity etc.
Usage of different kind of memories take place due to different kind of requirements from the system which cannot be fulfilled using one memory device.The requirement is based on saving time, decreasing complexity , improving performance etc.Example of requirements can be like some functions and files do not require much space , some might require quick accessing,etc.
Thus hierarchy of any particular system is in the form of fast to slow order from registers,cache memory, Random access memory(RAM) and secondary memory.
Answer:
the user should disable file and print sharing on the laptop
Explanation:
According to my research on information technology and cyber security, I can say that based on the information provided within the question in order to prevent this the user should disable file and print sharing on the laptop. This is because this file and printer sharing allows users to see your files that you have available as shared and copy or print those files. Which if they are sensitive data you should just disable this option so that people on the same network cannot see or access these files.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
void squareOfAsterisks(int x) //defining method squareOfAsterisks
{
int i,j; //defining integer variable
for(i=1;i<=x;i++) //defining loop to print column value
{
for(j=1;j<=x;j++) //defining loop to print row value
{
cout<<"*"; //print value
}
cout<<endl; //for line break
}
}
int main() //defining main method
{
int x; //defining integer variable
cout<<"Enter any number: "; //print message
cin>>x; //input value from user
squareOfAsterisks(x); //calling the method and pass the value
return 0;
}
Output:
Enter any number: 4
****
****
****
****
Explanation:
The description of the above program can be given as follows:
- In the given program a method "squareOfAsterisks" is declared, that accepts an integer value "x" in its arguments, inside the method two integer variable I, j is used, that uses a to print the given pattern.
- In the main method, an integer variable x is declared, which takes input from the user end, and then calls the method, that is "squareOfAsterisks" and passes its value.
Answer:
im sorry i dont understand
Explanation:
