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mojhsa [17]
3 years ago
7

After which stage in the information processing cycle can data be referred for future use?

Computers and Technology
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

after the data storage stage, data is able to be referred to and use for future uses.

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Analyzing Uses for PDFs
Sauron [17]

Answer:

You need to send a file to someone who does not have Word

Explanation:

In this case the answer is You need to send a file to someone who does not have Word.

But we use PDF to send files without changing its format.

4 0
3 years ago
GIVING BRAINLIEST
irakobra [83]

Answer:

A: Radio waves.

Explanation:

Computers use short-wave radio in order to communicate with devices in it's immediate vicinity.

8 0
2 years ago
Write a function called mul_time that takes a Time_Elapsed object and a number and returns a new Time_Elapsed object that contai
lisov135 [29]

# Write a function called mul_time that takes a Time object and a number and

# returns a new Time object that contains the product of the original Time and

# the number.

# Then use mul_time to write a function that takes a Time object that

# represents the finishing time in a race, and a number that represents the

# distance, and returns a Time object that represents the average pace (time

# per mile).

# Current Status: Complete

class Time(object):

   """ represents the time of day.

   attributes: hour, minute, second"""

time = Time()

time.hour = 3

time.minute = 0

time.second = 0

def time_to_int(time):

   minutes = time.hour * 60 + time.minute

   seconds = minutes * 60 + time.second

   return seconds

def int_to_time(seconds):

   new_time = Time()

   minutes, new_time.second = divmod(seconds, 60)

   time.hour, time.minute = divmod(minutes, 60)

   return time

def mul_time(time, multicand):

   time_int = time_to_int(time) * multicand

   new_time = int_to_time(time_int)

   if new_time.hour > 12:

       new_time.hour = new_time.hour % 12

#    print ("New time is: %.2d:%.2d:%.2d"

#    % (new_time.hour, new_time.minute, new_time.second))

   return new_time

# mul_time(time, 2)

def race_stats(time, distance):

   print ("The finish time was %.2d:%.2d:%.2d"

         % (time.hour, time.minute, time.second))

   print "The distance was %d miles" % (distance)

   average = mul_time(time, (1.0 / distance))

   print ("The average is: %.2d:%.2d:%.2d per mile"

         % (average.hour, average.minute, average.second))

race_stats(time, 3)

7 0
2 years ago
If given the chance to own manage a business,what will be the name of the business?
Nady [450]
This is honestly an answer you can give. What would you name a business if you made one?
7 0
3 years ago
Read 2 more answers
Assume the variable sales references a float value. Write a statement that displays the value rounded to two decimal points.Assu
romanna [79]

Answer:

The statement is as follows:

print("{0:,.1f}".format(number))

Explanation:

Required

Statement to print 1234567.456 as 1,234,567.5

To do this, we make use of the format keyword, and we set the print format in the process.

To round up number to 1 decimal place, we use the following format:

"{0:,.1f}"

To include comma in the thousand place, we simply include a comma sign before the number of decimal place of the output; i.e. before 1

"{0:,.1f}"

So, the print statement is:

print("{0:,.1f}".format(number))

3 0
3 years ago
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