Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.
If you would like to simplify<span> (3xy^2) * (4xy) * (2xy)^3, you can do this using the following steps:
</span>
(3xy^2) * (4xy) * (2xy)^3 = 3xy^2 * 4xy * 2^3x^3y^3 = 3 * 4 * 8 * x * x * x^3 * y^2 * y * y^3 = 96 * x^5 * y^6
The correct result would be 96 * x^5 * y^6.
Answer:
390 degrees
Step-by-step explanation:
The conversion factor is 180/pi
13 pi /6 * 180/pi
13/6 *180
390
Answer:
4x2 + 5 +
Step-by-step explanation:
please mark me brainliest please
maybe C? sorry i’m not the best at this