Answer:
2x² + 3x + 4 + (17x + 9) / (x² − 4)
Step-by-step explanation:
Start by setting up the division. Make sure to write all the coefficients, even the zero ones.
x² + 0x − 4 | 2x⁴ + 3x³ − 4x² + 5x − 7
Start by dividing the first term of the dividend (2x⁴) by the first term of the divisor (x²). That's 2x²; it'll be the first term in quotient. Multiply the divisor by 2x²:
2x⁴ + 0x³ − 8x²
Subtract that from the first three terms of the dividend:
3x³ + 4x²
Drop down the next term from the dividend, and start the process all over again.
3x³ + 4x² + 5x
When you finish, the quotient will be 2x² + 3x + 4, and the remainder will be 17x + 9.
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
Transitive Property
Step-by-step explanation:
Since X is the midpoint, it bisects the points RS. If MX=XS, and RS is the same as XS, then they are the same. This also follows the Transitive propety (if a=b and b=c, then a=c)
Answer:
Should be $300
let me know if it's correct:)
Answer:
Step-by-step explanation:
The shape above is a composite shape having two different shapes like rectangle and semi- circle
Area of rectangle=Length × Breadth
Area of semi circle=1/2πr^2
To find the area of the rectangle naw
Length of the rectangle=6.6
Width of the rectangle=4
A=6.6×4
A=26cm^2
Area of semi-circle=1/2
Diameter of the shape =4cm
Radius=2cm
A=1/2×3.14×2cm x2cm
A=6.28cm^2
Area of the shape=26+6.28cm^2
Area=32.28 to 2 dp
