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Blababa [14]
3 years ago
7

3x=10 how do you solve this, i hate math and dont know what to do. help?

Mathematics
2 answers:
blagie [28]3 years ago
6 0
Divide 3 on both sides
x=3.33
shutvik [7]3 years ago
5 0

Answer:

x = 10/3

Step-by-step explanation:

Okie so to solve a one variable equation, we have to isolate x. To do that, we have to divide both sides of the equation by 3 so we get x = 10/3.

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What does 124.06=2.35h+72.36<br> a.16<br> b.22<br> c.2.2<br> d.none of these
Arada [10]

Answer:

B. 22

Step-by-step explanation:

124.06 = 2.35h + 72.36

124.06 - 72.36 = 2.35h

51.7 = 2.35h

51.7/2.35 = h

22 = h

8 0
3 years ago
Check if the following pairs of fractions are equivalent.
d1i1m1o1n [39]

Answer:

They are equal

Step-by-step explanation: 3/3 = 1

                                             11/11 = 1

Hence, they are equal

8 0
2 years ago
Find the value of x. Round to the<br> nearest tenth.<br> 40<br> X<br> 7<br> x = [?]
serious [3.7K]
The correct answer for that question is 280
3 0
2 years ago
4x-5(-3) Help plzzzzzz​
kaheart [24]

Answer:

4x-15

Step-by-step explanation

You just multiply -5 and -3 to simplify this.

7 0
3 years ago
Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
2 years ago
Read 2 more answers
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